Mehapatel

Given, a galvanometer coil.Resistance on the galvanometer, R = 12 ΩCurrent on galvanometer, Ig =3 mA = 3 x 10–3 AVoltage ,V = 18 VBy using formula,                      V = Ig(R+Rg)                     VIg = R+Rg  or,                               R = VIg-Rg     = 183×10-3-12R = 6 × 103-12 = 5988Ω

Principle of potentiometer. The fall of potential along any length of the wire is directly proportional to that length. When a constant current flows through a wire of uniform cross-section and composition.V ∝ lComparison of emfs of two primary cells: The circuit diagram is shown in the figure.When the key K is closed, a constant current flows the potentiometer wire. By closing key K1, the cell E1 is included in the circuit. The jockey is adjusted till galvanometer shows no deflection. Suppose AJ1 = l1 is the balancing length for cell E1. ThenE1 = kl1where k is the potential gradient. Now the

∵   x4 - (y + z)4 = [x2]2 - [(y + z)2]2                       = [(x2) + (y + z)2] [(x2) - (y + z)2]                                                                                                      [Using a2 - b2 = (a+b)(a-b)]We can factorise [x2 - (y + z)2] further as       x2 - (y + z)2 = [(x) + (y + z)][(x) - (y + z)]                         = (x + y + z)(x - y - z)
∴      x4 - (y + z)4 = (x + y + z)(x - y - z)[x2 + (y + z)2]
     

R = {(x + 1), (x + 5) : x = 0, 1, 2, 3, 4, 5}= {(a, b) : x = 0, 1, 2, 3, 4, 5}When x = 0, a = 0 + 1 = 1, b = 0 + 5 = 5x = 1, a = 1 + 1 = 2, b = 1 + 5 = 6x = 2, a = 2 + 1= 3, b = 2 + 5 = 7x = 3,  a = 3 + 1 = 4, b = 3 + 5 =8x = 4, a = 4 + 1 = 5, b = 4 + 5 = 9x = 5, a = 5 + 1 =6, b = 5 + 5 = 10Hence,  R in the roster form is {(1, 5), (2, 6), (3, 7), (4, 8), (5, 9), (6, 10)}Domain of R = {1, 2, 3, 4, 5, 6}Range of R = {5, 6, 7, 8, 9, 10}

One of the reaction that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO2.

Given,
Inner radius of torroid core, rl
Outer radius, r2 = 0.26 m
Number of turns, N = 3500
Current in the wire, I = 11 A
= 0.25 m
(i) The magnetic field is zero outside the toroid because, there is no current flowing on
outside of the torroid.
(ii) Magnetic field inside the core of the toroid,

Language policy of India:
1. Our Constitution did not give the status of national language to any one language. Hindi was identified as the official language. But Hindi is the mother tongue of only about 40 per cent of the Indians. Therefore, there were many safeguards to protect other languages.
2. Besides Hindi, there are 21 other languages recognised as scheduled languages by the Constitution.
3. A candidate in an examination conducted for the national government positions may opt to take the examination in any of these languages. States too have their own official languages. Much of th

Answer -: +ve x direction with frequency 1 Hz and wavelength A = 0.2 m
The sign between two terms in the argument of sine will define its direction.
Writing the given wave equation
y= 0.25 sin (10 Toe- 2t .. (i)
The minus () between (10mx) and (2rt) implies that the waves is travelling along the positive x-direction.
Now comparing eq (i) with standard wave equation
y=asin (kx-wt) ... (i)
we have

i) Fe exists in the +3 oxidation state i.e, in d5 configuration.Since water is the weak ligand, therefore, there is no paired electron. Hence it is strongly paramagnetic and high spin.  Hybridization sp3d2.ii) 

(i) The poet wants us to keep quiet and give up endless activity to be able to introspect. He wants us to break free of the barriers of language and be united in a moment of eloquent silence.(ii) The poet wants us to give up our endless, incessant activities and be lost in eloquent, calm and peaceful silence break free of all barriers of language and communication.(iii) When the poet says ‘ not move our arms’, he wishes to convey that in the moment of eloquent peaceful silence we must all give up whatever we are doing. He means to say there must be absolutely no action, no activity and no com

हमारे विचार में महानवमी डिब्बा से संबद्ध अनुष्ठानों का व्यापक महत्त्व था। विजयनगर शहरों के सबसे ऊँचे स्थानों पर महानवमी डिब्बा नमक विशाल मंच होता था।
इस संरचना से जुड़ेअनुष्ठान, संभवत: सितंबर तथा अक्टूबर के शरद मासों में मनाए जाने वाले दस दिन के हिंदू त्यौहार, जिसे दशहरा (उत्तर भारत), दुर्गा पूजा (बंगाल में) तथा नवरात्री या महानवमी (प्रायद्वीपीय भारत में) नामों से जाना जाता है, के महानवमी के अवसर पर निष्पादित किए जाते थे। इस अवसर पर विजयनगर शासक अपने रुतबे, ताकत तथा अधिराज्य का प्रदर्शन करते थे।
इस अवसर पर होने वाले अनुष्ठानों में मूर्तिपूजा, अश्व-पूजा के साथ-साथ भैंसों तथा अन्य जानवरों की ब

Shehnai is an improved version of pungi as it has a better tonal quality than pungi. It is a natural hollow stem pipe  with seven holes on its body and is longer and broader than the pungi. 

John Keats is a poet of nature. He sees beauty in all the natural objects since a thing of beauty is a joy for ever. According to him every thing of nature is a source of beauty. In the poem we can see, the sun, the moon, the trees, daffodils, green forests, clear rills, masses of ferns, blooming musk-rose and lovely tales, etc. These beautiful sources provide pleasure and joy to the mankind.

The difference:Potential Resources: Resources which are found in a region, but have not been utilised due to lack of capital or other reasons. For example, the western parts of India, particularly Rajasthan and Gujarat have enormous potential for the development of wind and solar energy, but so far, these have not been developed properly.
Stock Resources: Materials in the environment which have the potential to satisfy human needs but human beings do not have the appropriate technology to access these, are included among stock.
For example, water is a compound of two inflammable gases; hyd

Aunt Jennifer is busy knitting with her ivory needle through her wool. But the chores and duties of the family checked her in the middle, she had to stop knitting. ‘Massive weight of uncle’s wedding band’ represents the marriage band between Jennifer and uncle. It suggests the harsh and difficult experiences of her married life. After marriage she had lost all her freedom. Aunt was like a heavy band put on her.

Mechanism: The formation of ethylene and diethyl ether from ethanol and conc. H2SO4 may be explained as follows:(a) Formation of ethene or ethylene:Step 1. Due to the presence of two lone pairs of electrons on oxygen, alcohols act as weak bases. Therefore, they react with strong mineral acids (HCl, H2SO4 etc.) to form oxonium salts.Step 2. The presence of a positive charge on the highly electronegative oxygen atom weakens the C—O bond. Thus, the protonated ethanol readily eliminates a molecule of H2O to form ethyl carbocation.This step is slow and hence is the rate-determining step of the rea

Mrs Pearson and Mrs Fitzgerald are two contrasting characters. Actually, they are foil to each other. Mrs Pearson is a pleasant looking woman in her forties. She appears to be confused and worried. Mrs Fitzgerald is older. She is heavier and has a ‘strong and sinister personality’. Mrs Pearson is timid and gentle. Mrs Fitzgerald is liberated and bold. She smokes and plays with cards. The two ladies have sharply contrasting voices. Mrs Pearson speaks in a ‘light, flurried sort of tone’. She has ‘a touch of suburban Cockney’. Mrs Fitzgerald has a deep voice. Her accent is Irish.
Mrs Pearson ha

Crystal Field Splitting Energy: Crystal field theory was given to explain the structure and stability of the coordination complexes. This theory has some assumption like the metal ion is considered to be a point positive charge and the ligands are negative charge. The complexes are formed mainly by the d- block elements due to their variable oxidation states and variable coordination number. The d- subshell has 5 degenerate orbitals. when the ligand approach to the metal ion, the energy of the degenerate orbitals is increased and further splitting of degenerate orbital takes place into t2g an

Here,          Frequency of the plane EM wave, v = 2 × 1010HzAmplitude of electric field,  E0 = 48 Vm-1  Therefore, Wavelength of the wave, λ = cv =3 × 1082 × 1010m = 1.5 × 10-2m Amplitude of oscillating magnetic field,B0 = E0c = 483 × 108T = 1.6 × 10-7T Energy density in electric field,          μE = 12 ε0 E2Energy density in magnetic field,         μB = 12μ0B2 Using the relation, we have                  E = cB,  uE = 12 ε0 (cB)2     = c2 12 ε0 B2 But,           c = 1μ0 ε0 ∴ μE = 1μ0 ε012ε0B2 = 12μ0B2 = μB Hence, the average energy density of electric field equals the average energy density

Kinetic energy of particle of mass m having momentum p is,                    K.E = 12p2m ⇒                  p = 2mK De-Broglie wavelength, λ = hp = h2mK ∴                                p = hλ                  ....(i)and,                                   K = h22mλ2             ....(ii) If λ is constant, then from equation (i), p = constant. i.e.,               mpvp = meve                           vpve = memp