Mehapatel

(a) (i) 858843 (ii) 834916
(b) (i) 8189 (ii) 8088
(c) Scale of the map 2 cm = 1 km Shortest Distance 8 cm = 8/2 = 4 km.
(d) (i) Broken ground
(ii) Water channel
(e) (i) The general pattern of settlements is scattered or dispersed.(ii) Large farms are there, but availability of water is less due to which this region has sparse population which is scattered all over in search of water.
(f) The chief form of irrigation is perennial wells. It is necessary because this area gets seasonal rainfall which is not enough for cultivation. Wells are the only source which provide water throughout th

Difference between globular protein and fibrous protein:

Fibrous protein


Globular protein
 


1.It is a fibre-like structure formed by the
polypeptide chain. These proteins are held
together by strong hydrogen and disulphide
bonds


1.
The polypeptide chain in this
protein is folded around itself,
giving rise to a spherical
Structure.
 


2. It is usually insoluble in water, but soluble in strong acids and bases.


2. It is usually soluble in water, acids, bases and salts.
 


3. They have comparatively stronger intermolecular forces of attraction.


3. The

In ΔABC,     In ΔBED,∴  Speed of the aeroplane            

The similarity between Li and Mg is because of their similar atomic radii (Li = 152 pm; Mg = 160 pm) and ionic radii. (Li+ = 76 pm,  Mg2+ = 72 pm).These two elements resemble each other in the following properties:(i) Both Li and Mg decompose water very slowly with the liberation of hydrogen.(ii) Both Li and Mg form nitrides  - Li directly and Mg on burning in nitrogen.(iii) LiOH and Mg(OH)2 are weak bases. (iv) Nitrates of both decompose on heating to give oxides.                  (v) Both LiCl and MgCl2 are soluble in ethanol. (vi) Both LiCl and MgCl2 are deliquescent and crystalline from a

Here,Inductance, L = 80 mH = 80 x 10-3H Capacitance, C = 60 μF = 60 × 10-6F Resistance, R = 0RMS voltage, Ev = 230 VPeak voltage, E0 = 2 ×Ev                                = 2 × 230 V Frequency of Ac supply,  f = 50 Hz ∴  ω = 2πf           = 100  π rad/s (a) We have to find I0 = ?,   Iv = ? Therefore,             I0 = E0ωL -1ωL     = 230 2100 π × 80 × 10-3 - 1100 π × 60 × 10-6   = 230 28π -10006π = 230 2-27.91 = -11.63 amp.and,Iv = I02 =-11.631.414 = -8.23 amp.  Negative sign appears as ωL

The pair of curves (1, 3) and (2, 4) corresponds to different materials but having same intensity of incident radiation. The value of stopping potential for the curves (1, 2) and (3, 4) is same implying that they correspond to similar materials. 

gsebe Textbook Solutions Class 12 Economics. Free online Economics Textbook Questions and Answers. Students can find Economics 2018-19 syllabus, marking scheme, solved sample papers and previous year papers

Metal oxide = M0.98O If ‘x’ ions of M are in +3 state, then 3x + (0.98 – x) × 2 = 2 x = 0.04 So the percentage of metal in +3 state would be

NO(g) Br2 (g) ⇌ NOBr2 (g)NOBr2 (g) NO(g)→ 2NOBr(g)R = K[NOBr2][NO]= K.Kc[NO][Br2][NO], ==K [NO]2 [Br2 ]

Co-factors of the elements of the first row of | A | are
i.e. 3,  1, – 1 respectivelyCo-factors of the elements of the second row of | A | arei.e.   I,  3,  I respectivelyCo-factors of the elements of the third row of | A | arei.e. 1, 1, 3 respectively

Private Sector Health Infrastructure in India : In recent time private sector has been playing a dominant role in health structures as it is clear from the following points:
1. More than 70 percent of the hospitals in India are run by the private sector.
2. They control nearly two fifth of beds available in the hospitals.
3. Nearly 60 percent of dispensaries are run by private sector.
4. Private sector provides healthcare for 80 percent of out-patients and 46 percent of in-patients.
5. It has been playing a dominant role in medical education and training, medical technology and diagnosti

     Batsman A (nearly)C.V. =   (approx.)Bastman B                                                 S.D. =           C.V. = Hence, the scores of batsman A are more consistent and those of batsman B are more variable.

Net work done in sliding a body up to a height h on inclined plane    = Work done against gravitational force + Work done against frictional force 

हमारे विचार में महानवमी डिब्बा से संबद्ध अनुष्ठानों का व्यापक महत्त्व था। विजयनगर शहरों के सबसे ऊँचे स्थानों पर महानवमी डिब्बा नमक विशाल मंच होता था।
इस संरचना से जुड़ेअनुष्ठान, संभवत: सितंबर तथा अक्टूबर के शरद मासों में मनाए जाने वाले दस दिन के हिंदू त्यौहार, जिसे दशहरा (उत्तर भारत), दुर्गा पूजा (बंगाल में) तथा नवरात्री या महानवमी (प्रायद्वीपीय भारत में) नामों से जाना जाता है, के महानवमी के अवसर पर निष्पादित किए जाते थे। इस अवसर पर विजयनगर शासक अपने रुतबे, ताकत तथा अधिराज्य का प्रदर्शन करते थे।
इस अवसर पर होने वाले अनुष्ठानों में मूर्तिपूजा, अश्व-पूजा के साथ-साथ भैंसों तथा अन्य जानवरों की ब

Kinetic energy of particle of mass m having momentum p is,                    K.E = 12p2m ⇒                  p = 2mK De-Broglie wavelength, λ = hp = h2mK ∴                                p = hλ                  ....(i)and,                                   K = h22mλ2             ....(ii) If λ is constant, then from equation (i), p = constant. i.e.,               mpvp = meve                           vpve = memp

Here,          Frequency of the plane EM wave, v = 2 × 1010HzAmplitude of electric field,  E0 = 48 Vm-1  Therefore, Wavelength of the wave, λ = cv =3 × 1082 × 1010m = 1.5 × 10-2m Amplitude of oscillating magnetic field,B0 = E0c = 483 × 108T = 1.6 × 10-7T Energy density in electric field,          μE = 12 ε0 E2Energy density in magnetic field,         μB = 12μ0B2 Using the relation, we have                  E = cB,  uE = 12 ε0 (cB)2     = c2 12 ε0 B2 But,           c = 1μ0 ε0 ∴ μE = 1μ0 ε012ε0B2 = 12μ0B2 = μB Hence, the average energy density of electric field equals the average energy density

Crystal Field Splitting Energy: Crystal field theory was given to explain the structure and stability of the coordination complexes. This theory has some assumption like the metal ion is considered to be a point positive charge and the ligands are negative charge. The complexes are formed mainly by the d- block elements due to their variable oxidation states and variable coordination number. The d- subshell has 5 degenerate orbitals. when the ligand approach to the metal ion, the energy of the degenerate orbitals is increased and further splitting of degenerate orbital takes place into t2g an

Mrs Pearson and Mrs Fitzgerald are two contrasting characters. Actually, they are foil to each other. Mrs Pearson is a pleasant looking woman in her forties. She appears to be confused and worried. Mrs Fitzgerald is older. She is heavier and has a ‘strong and sinister personality’. Mrs Pearson is timid and gentle. Mrs Fitzgerald is liberated and bold. She smokes and plays with cards. The two ladies have sharply contrasting voices. Mrs Pearson speaks in a ‘light, flurried sort of tone’. She has ‘a touch of suburban Cockney’. Mrs Fitzgerald has a deep voice. Her accent is Irish.
Mrs Pearson ha

Mechanism: The formation of ethylene and diethyl ether from ethanol and conc. H2SO4 may be explained as follows:(a) Formation of ethene or ethylene:Step 1. Due to the presence of two lone pairs of electrons on oxygen, alcohols act as weak bases. Therefore, they react with strong mineral acids (HCl, H2SO4 etc.) to form oxonium salts.Step 2. The presence of a positive charge on the highly electronegative oxygen atom weakens the C—O bond. Thus, the protonated ethanol readily eliminates a molecule of H2O to form ethyl carbocation.This step is slow and hence is the rate-determining step of the rea

Aunt Jennifer is busy knitting with her ivory needle through her wool. But the chores and duties of the family checked her in the middle, she had to stop knitting. ‘Massive weight of uncle’s wedding band’ represents the marriage band between Jennifer and uncle. It suggests the harsh and difficult experiences of her married life. After marriage she had lost all her freedom. Aunt was like a heavy band put on her.