a galvanometer coil has a resistance 12ω and the meter shows full scale deflection for a current of 3ma.how will you | Dofollow Social Bookmarking Sites 2016
Facing issue in account approval? email us at info@ipt.pw

Click to Ckeck Our - FREE SEO TOOLS

1
Given, a galvanometer coil.Resistance on the galvanometer, R = 12 ΩCurrent on galvanometer, Ig =3 mA = 3 x 10–3 AVoltage ,V = 18 VBy using formula,                      V = Ig(R+Rg)                     VIg = R+Rg  or,                               R = VIg-Rg     = 183×10-3-12R = 6 × 103-12 = 5988Ω

Comments

Who Upvoted this Story

Search

Latest Comments
Published News